-16x^2+0x+200=0

Solution for -16x^2+0x+200=0 equation:

-16x^2+0x+200=0

We add all the numbers together, and all the variables

-16x^2+x+200=0

a = -16; b = 1; c = +200;
Δ = b2-4ac
Δ = 12-4·(-16)·200
Δ = 12801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{12801}}{2*-16}=\frac{-1-\sqrt{12801}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{12801}}{2*-16}=\frac{-1+\sqrt{12801}}{-32}
$